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113224431293 is a prime number
BaseRepresentation
bin110100101110010110…
…0111011011010111101
3101211020210202001120022
41221130230323122331
53323340423300133
6124003052301525
711115543533531
oct1513454733275
9354223661508
10113224431293
1144022270066
1219b3a7718a5
13a8a5540b0c
1456a152bbc1
152e2a21e998
hex1a5cb3b6bd

113224431293 has 2 divisors, whose sum is σ = 113224431294. Its totient is φ = 113224431292.

The previous prime is 113224431289. The next prime is 113224431337. The reversal of 113224431293 is 392134422311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103299888409 + 9924542884 = 321403^2 + 99622^2 .

It is an emirp because it is prime and its reverse (392134422311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113224431293 - 22 = 113224431289 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113224431223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56612215646 + 56612215647.

It is an arithmetic number, because the mean of its divisors is an integer number (56612215647).

Almost surely, 2113224431293 is an apocalyptic number.

It is an amenable number.

113224431293 is a deficient number, since it is larger than the sum of its proper divisors (1).

113224431293 is an equidigital number, since it uses as much as digits as its factorization.

113224431293 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 35.

The spelling of 113224431293 in words is "one hundred thirteen billion, two hundred twenty-four million, four hundred thirty-one thousand, two hundred ninety-three".