Base | Representation |
---|---|
bin | 10101000101110011… |
… | …01100011101011001 |
3 | 1002020010011100220101 |
4 | 22202321230131121 |
5 | 141142134433042 |
6 | 5111322255401 |
7 | 550410432133 |
oct | 124271543531 |
9 | 32203140811 |
10 | 11322967897 |
11 | 489057a40a |
12 | 2240057561 |
13 | 10b5b07707 |
14 | 795b42053 |
15 | 4640d86b7 |
hex | 2a2e6c759 |
11322967897 has 2 divisors, whose sum is σ = 11322967898. Its totient is φ = 11322967896.
The previous prime is 11322967889. The next prime is 11322967913. The reversal of 11322967897 is 79876922311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9130949136 + 2192018761 = 95556^2 + 46819^2 .
It is an emirp because it is prime and its reverse (79876922311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11322967897 - 23 = 11322967889 is a prime.
It is not a weakly prime, because it can be changed into another prime (11322967867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661483948 + 5661483949.
It is an arithmetic number, because the mean of its divisors is an integer number (5661483949).
Almost surely, 211322967897 is an apocalyptic number.
It is an amenable number.
11322967897 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322967897 is an equidigital number, since it uses as much as digits as its factorization.
11322967897 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2286144, while the sum is 55.
The spelling of 11322967897 in words is "eleven billion, three hundred twenty-two million, nine hundred sixty-seven thousand, eight hundred ninety-seven".
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