Base | Representation |
---|---|
bin | 11001101111101101110001… |
… | …111011100001111110010000 |
3 | 112211220200202202000112100210 |
4 | 121233231301323201332100 |
5 | 104320130303332134004 |
6 | 1040453112223044120 |
7 | 32564415165623160 |
oct | 3157556173417620 |
9 | 484820682015323 |
10 | 113230134255504 |
11 | 330956a297a262 |
12 | 10848912a40640 |
13 | 4b2472c261036 |
14 | 1dd65211105a0 |
15 | d15597bc4089 |
hex | 66fb71ee1f90 |
113230134255504 has 80 divisors (see below), whose sum is σ = 345082313953280. Its totient is φ = 31307871219840.
The previous prime is 113230134255499. The next prime is 113230134255517. The reversal of 113230134255504 is 405552431032311.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5435383894 + ... + 5435404725.
It is an arithmetic number, because the mean of its divisors is an integer number (4313528924416).
Almost surely, 2113230134255504 is an apocalyptic number.
113230134255504 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
113230134255504 is an abundant number, since it is smaller than the sum of its proper divisors (231852179697776).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113230134255504 is a wasteful number, since it uses less digits than its factorization.
113230134255504 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10870788668 (or 10870788662 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 113230134255504 its reverse (405552431032311), we get a palindrome (518782565287815).
The spelling of 113230134255504 in words is "one hundred thirteen trillion, two hundred thirty billion, one hundred thirty-four million, two hundred fifty-five thousand, five hundred four".
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