113230142437 has 2 divisors, whose sum is σ = 113230142438. Its totient is φ = 113230142436.

The previous prime is 113230142411. The next prime is 113230142447. The reversal of 113230142437 is 734241032311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111800621956 + 1429520481 = 334366^2 + 37809^2 .

It is a cyclic number.

It is not a de Polignac number, because 113230142437 - 2¹⁵ = 113230109669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113230142399 and 113230142408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113230142447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615071218 + 56615071219.

It is an arithmetic number, because the mean of its divisors is an integer number (56615071219).

Almost surely, 2^113230142437 is an apocalyptic number.

It is an amenable number.

113230142437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113230142437 is an equidigital number, since it uses as much as digits as its factorization.

113230142437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 113230142437 its reverse (734241032311), we get a palindrome (847471174748).

The spelling of 113230142437 in words is "one hundred thirteen billion, two hundred thirty million, one hundred forty-two thousand, four hundred thirty-seven".