Base | Representation |
---|---|
bin | 10000011110100010100… |
… | …000101111001111101001 |
3 | 11000020200010122121020122 |
4 | 100132202200233033221 |
5 | 122022424014434321 |
6 | 2224101152333025 |
7 | 144543343522205 |
oct | 20364240571751 |
9 | 4006603577218 |
10 | 1132302889961 |
11 | 3a723050a371 |
12 | 163545b44175 |
13 | 82a112b7a49 |
14 | 3cb376d3b05 |
15 | 1e6c186c8ab |
hex | 107a282f3e9 |
1132302889961 has 2 divisors, whose sum is σ = 1132302889962. Its totient is φ = 1132302889960.
The previous prime is 1132302889957. The next prime is 1132302889973. The reversal of 1132302889961 is 1699882032311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 851318083561 + 280984806400 = 922669^2 + 530080^2 .
It is a cyclic number.
It is not a de Polignac number, because 1132302889961 - 22 = 1132302889957 is a prime.
It is a super-2 number, since 2×11323028899612 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1132302889901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566151444980 + 566151444981.
It is an arithmetic number, because the mean of its divisors is an integer number (566151444981).
Almost surely, 21132302889961 is an apocalyptic number.
It is an amenable number.
1132302889961 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132302889961 is an equidigital number, since it uses as much as digits as its factorization.
1132302889961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1119744, while the sum is 53.
The spelling of 1132302889961 in words is "one trillion, one hundred thirty-two billion, three hundred two million, eight hundred eighty-nine thousand, nine hundred sixty-one".
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