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11323030033177 is a prime number
BaseRepresentation
bin1010010011000101100100…
…1011101101001100011001
31111002110201102122121102021
42210301121023231030121
52441004031142030202
640025421142134441
72246030145152602
oct244613113551431
944073642577367
1011323030033177
113676085298a85
12132a58ba21421
136419ac5c8c15
142b2075182da9
15149810b0ba37
hexa4c592ed319

11323030033177 has 2 divisors, whose sum is σ = 11323030033178. Its totient is φ = 11323030033176.

The previous prime is 11323030033171. The next prime is 11323030033267. The reversal of 11323030033177 is 77133003032311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11115849393936 + 207180639241 = 3334044^2 + 455171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11323030033177 is a prime.

It is a super-2 number, since 2×113230300331772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11323030033171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661515016588 + 5661515016589.

It is an arithmetic number, because the mean of its divisors is an integer number (5661515016589).

Almost surely, 211323030033177 is an apocalyptic number.

It is an amenable number.

11323030033177 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323030033177 is an equidigital number, since it uses as much as digits as its factorization.

11323030033177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23814, while the sum is 34.

Adding to 11323030033177 its reverse (77133003032311), we get a palindrome (88456033065488).

The spelling of 11323030033177 in words is "eleven trillion, three hundred twenty-three billion, thirty million, thirty-three thousand, one hundred seventy-seven".