Base | Representation |
---|---|
bin | 1010010011000101100101… |
… | …0100011110000001101011 |
3 | 1111002110201120222022112122 |
4 | 2210301121110132001223 |
5 | 2441004032234032342 |
6 | 40025421303301455 |
7 | 2246030203531103 |
oct | 244613124360153 |
9 | 44073646868478 |
10 | 11323032330347 |
11 | 3676086617971 |
12 | 132a59074a88b |
13 | 6419acc216aa |
14 | 2b20755c0203 |
15 | 149810e124d2 |
hex | a4c5951e06b |
11323032330347 has 2 divisors, whose sum is σ = 11323032330348. Its totient is φ = 11323032330346.
The previous prime is 11323032330289. The next prime is 11323032330353. The reversal of 11323032330347 is 74303323032311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11323032330347 - 26 = 11323032330283 is a prime.
It is a super-2 number, since 2×113230323303472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11323032330367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661516165173 + 5661516165174.
It is an arithmetic number, because the mean of its divisors is an integer number (5661516165174).
Almost surely, 211323032330347 is an apocalyptic number.
11323032330347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323032330347 is an equidigital number, since it uses as much as digits as its factorization.
11323032330347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 35.
Adding to 11323032330347 its reverse (74303323032311), we get a palindrome (85626355362658).
The spelling of 11323032330347 in words is "eleven trillion, three hundred twenty-three billion, thirty-two million, three hundred thirty thousand, three hundred forty-seven".
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