Base | Representation |
---|---|
bin | 1010010011000101110101… |
… | …1011100111000011101111 |
3 | 1111002110220101202220111121 |
4 | 2210301131123213003233 |
5 | 2441004202413424330 |
6 | 40025432210001411 |
7 | 2246032002051361 |
oct | 244613533470357 |
9 | 44073811686447 |
10 | 11323101311215 |
11 | 3676111552251 |
12 | 132a5ab876267 |
13 | 6419c12c4385 |
14 | 2b2080818d31 |
15 | 149816edb17a |
hex | a4c5d6e70ef |
11323101311215 has 16 divisors (see below), whose sum is σ = 13641637161600. Its totient is φ = 9022555837440.
The previous prime is 11323101311107. The next prime is 11323101311281. The reversal of 11323101311215 is 51211310132311.
It is not a de Polignac number, because 11323101311215 - 211 = 11323101309167 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11323101311215.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3745861 + ... + 6056209.
It is an arithmetic number, because the mean of its divisors is an integer number (852602322600).
Almost surely, 211323101311215 is an apocalyptic number.
11323101311215 is a deficient number, since it is larger than the sum of its proper divisors (2318535850385).
11323101311215 is a wasteful number, since it uses less digits than its factorization.
11323101311215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2314242.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 11323101311215 its reverse (51211310132311), we get a palindrome (62534411443526).
The spelling of 11323101311215 in words is "eleven trillion, three hundred twenty-three billion, one hundred one million, three hundred eleven thousand, two hundred fifteen".
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