Base | Representation |
---|---|
bin | 11001101111101110101100… |
… | …001101110111110111001011 |
3 | 112211220210021220002022211122 |
4 | 121233232230031313313023 |
5 | 104320134304202023113 |
6 | 1040453353234345455 |
7 | 32564451341544062 |
oct | 3157565415676713 |
9 | 484823256068748 |
10 | 113231112142283 |
11 | 3309605496a053 |
12 | 10848b4642b28b |
13 | 4b24856a27c75 |
14 | 1dd65b4d431d9 |
15 | d15603988408 |
hex | 66fbac377dcb |
113231112142283 has 2 divisors, whose sum is σ = 113231112142284. Its totient is φ = 113231112142282.
The previous prime is 113231112142273. The next prime is 113231112142319. The reversal of 113231112142283 is 382241211132311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113231112142283 is a prime.
It is not a weakly prime, because it can be changed into another prime (113231112142273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615556071141 + 56615556071142.
It is an arithmetic number, because the mean of its divisors is an integer number (56615556071142).
Almost surely, 2113231112142283 is an apocalyptic number.
113231112142283 is a deficient number, since it is larger than the sum of its proper divisors (1).
113231112142283 is an equidigital number, since it uses as much as digits as its factorization.
113231112142283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13824, while the sum is 35.
Adding to 113231112142283 its reverse (382241211132311), we get a palindrome (495472323274594).
The spelling of 113231112142283 in words is "one hundred thirteen trillion, two hundred thirty-one billion, one hundred twelve million, one hundred forty-two thousand, two hundred eighty-three".
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