Base | Representation |
---|---|
bin | 10000011110100011001… |
… | …000011101000101010011 |
3 | 11000020200212020112221221 |
4 | 100132203020131011103 |
5 | 122022434201120311 |
6 | 2224102203425511 |
7 | 144543531154102 |
oct | 20364310350523 |
9 | 4006625215857 |
10 | 1132313301331 |
11 | 3a7236380603 |
12 | 163549525297 |
13 | 82a134c1914 |
14 | 3cb38c44039 |
15 | 1e6c2727671 |
hex | 107a321d153 |
1132313301331 has 2 divisors, whose sum is σ = 1132313301332. Its totient is φ = 1132313301330.
The previous prime is 1132313301269. The next prime is 1132313301359. The reversal of 1132313301331 is 1331033132311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1132313301331 - 227 = 1132179083603 is a prime.
It is a super-2 number, since 2×11323133013312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1132313301296 and 1132313301305.
It is not a weakly prime, because it can be changed into another prime (1132313301391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566156650665 + 566156650666.
It is an arithmetic number, because the mean of its divisors is an integer number (566156650666).
Almost surely, 21132313301331 is an apocalyptic number.
1132313301331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132313301331 is an equidigital number, since it uses as much as digits as its factorization.
1132313301331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1132313301331 its reverse (1331033132311), we get a palindrome (2463346433642).
The spelling of 1132313301331 in words is "one trillion, one hundred thirty-two billion, three hundred thirteen million, three hundred one thousand, three hundred thirty-one".
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