Base | Representation |
---|---|
bin | 1010010011000110010100… |
… | …0110100001100001011011 |
3 | 1111002111020100221001000221 |
4 | 2210301211012201201123 |
5 | 2441004433340014433 |
6 | 40025453044140511 |
7 | 2246035123645066 |
oct | 244614506414133 |
9 | 44074210831027 |
10 | 11323230001243 |
11 | 3676178159a46 |
12 | 132a626997737 |
13 | 641a11b71814 |
14 | 2b20939578dd |
15 | 14982345b72d |
hex | a4c651a185b |
11323230001243 has 2 divisors, whose sum is σ = 11323230001244. Its totient is φ = 11323230001242.
The previous prime is 11323230001211. The next prime is 11323230001297. The reversal of 11323230001243 is 34210003232311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11323230001243 - 25 = 11323230001211 is a prime.
It is a super-2 number, since 2×113232300012432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11323230001543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661615000621 + 5661615000622.
It is an arithmetic number, because the mean of its divisors is an integer number (5661615000622).
Almost surely, 211323230001243 is an apocalyptic number.
11323230001243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323230001243 is an equidigital number, since it uses as much as digits as its factorization.
11323230001243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 11323230001243 its reverse (34210003232311), we get a palindrome (45533233233554).
The spelling of 11323230001243 in words is "eleven trillion, three hundred twenty-three billion, two hundred thirty million, one thousand, two hundred forty-three".
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