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113233011330 = 2353774433711
BaseRepresentation
bin110100101110100110…
…1101010001010000010
3101211021101212222011110
41221131031222022002
53323400122330310
6124004000224150
711116006500315
oct1513515521202
9354241788143
10113233011330
11440270a03aa
1219b4160b056
13a8a725626a
1456a272297c
152e2ad66d20
hex1a5d36a282

113233011330 has 16 divisors (see below), whose sum is σ = 271759227264. Its totient is φ = 30195469680.

The previous prime is 113233011289. The next prime is 113233011343. The reversal of 113233011330 is 33110332311.

It is a junction number, because it is equal to n+sod(n) for n = 113233011297 and 113233011306.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1887216826 + ... + 1887216885.

It is an arithmetic number, because the mean of its divisors is an integer number (16984951704).

Almost surely, 2113233011330 is an apocalyptic number.

113233011330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113233011330 is an abundant number, since it is smaller than the sum of its proper divisors (158526215934).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113233011330 is a wasteful number, since it uses less digits than its factorization.

113233011330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3774433721.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 113233011330 its reverse (33110332311), we get a palindrome (146343343641).

The spelling of 113233011330 in words is "one hundred thirteen billion, two hundred thirty-three million, eleven thousand, three hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 3774433711 7548867422 11323301133 18872168555 22646602266 37744337110 56616505665 113233011330