Base | Representation |
---|---|
bin | 1010010011000110100101… |
… | …1001100100010111111011 |
3 | 1111002111102101121011101201 |
4 | 2210301221121210113323 |
5 | 2441010110314240043 |
6 | 40025504141355031 |
7 | 2246036660542645 |
oct | 244615131442773 |
9 | 44074371534351 |
10 | 11323302102523 |
11 | 3676204925784 |
12 | 132a646b68a77 |
13 | 641a23a978b8 |
14 | 2b209d365895 |
15 | 14982994ec4d |
hex | a4c696645fb |
11323302102523 has 2 divisors, whose sum is σ = 11323302102524. Its totient is φ = 11323302102522.
The previous prime is 11323302102509. The next prime is 11323302102587. The reversal of 11323302102523 is 32520120332311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11323302102523 - 217 = 11323301971451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11323302102491 and 11323302102500.
It is not a weakly prime, because it can be changed into another prime (11323302102503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661651051261 + 5661651051262.
It is an arithmetic number, because the mean of its divisors is an integer number (5661651051262).
Almost surely, 211323302102523 is an apocalyptic number.
11323302102523 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323302102523 is an equidigital number, since it uses as much as digits as its factorization.
11323302102523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 11323302102523 its reverse (32520120332311), we get a palindrome (43843422434834).
The spelling of 11323302102523 in words is "eleven trillion, three hundred twenty-three billion, three hundred two million, one hundred two thousand, five hundred twenty-three".
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