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113233030301113 is a prime number
BaseRepresentation
bin11001101111110000011110…
…100011000100010110111001
3112211220222020120102220002021
4121233300132203010112321
5104320202221224113423
61040454311435234441
732564550022613632
oct3157603643042671
9484828216386067
10113233030301113
1133096949698188
12108493a08a8a21
134b24aa1248ba8
141dd67179b6889
15d156b708195d
hex66fc1e8c45b9

113233030301113 has 2 divisors, whose sum is σ = 113233030301114. Its totient is φ = 113233030301112.

The previous prime is 113233030301089. The next prime is 113233030301129. The reversal of 113233030301113 is 311103030332311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86341784352784 + 26891245948329 = 9292028^2 + 5185677^2 .

It is a cyclic number.

It is not a de Polignac number, because 113233030301113 - 25 = 113233030301081 is a prime.

It is not a weakly prime, because it can be changed into another prime (113233030301143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56616515150556 + 56616515150557.

It is an arithmetic number, because the mean of its divisors is an integer number (56616515150557).

Almost surely, 2113233030301113 is an apocalyptic number.

It is an amenable number.

113233030301113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113233030301113 is an equidigital number, since it uses as much as digits as its factorization.

113233030301113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 113233030301113 its reverse (311103030332311), we get a palindrome (424336060633424).

The spelling of 113233030301113 in words is "one hundred thirteen trillion, two hundred thirty-three billion, thirty million, three hundred one thousand, one hundred thirteen".