Base | Representation |
---|---|
bin | 11001101111110000011110… |
… | …100011000100011000010111 |
3 | 112211220222020120102220012202 |
4 | 121233300132203010120113 |
5 | 104320202221224114312 |
6 | 1040454311435235115 |
7 | 32564550022614125 |
oct | 3157603643043027 |
9 | 484828216386182 |
10 | 113233030301207 |
11 | 33096949698263 |
12 | 108493a08a8a9b |
13 | 4b24aa1248c4b |
14 | 1dd67179b6915 |
15 | d156b70819c2 |
hex | 66fc1e8c4617 |
113233030301207 has 2 divisors, whose sum is σ = 113233030301208. Its totient is φ = 113233030301206.
The previous prime is 113233030301197. The next prime is 113233030301227. The reversal of 113233030301207 is 702103030332311.
It is a weak prime.
It is an emirp because it is prime and its reverse (702103030332311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113233030301207 - 24 = 113233030301191 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113233030301207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113233030301227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56616515150603 + 56616515150604.
It is an arithmetic number, because the mean of its divisors is an integer number (56616515150604).
Almost surely, 2113233030301207 is an apocalyptic number.
113233030301207 is a deficient number, since it is larger than the sum of its proper divisors (1).
113233030301207 is an equidigital number, since it uses as much as digits as its factorization.
113233030301207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 29.
Adding to 113233030301207 its reverse (702103030332311), we get a palindrome (815336060633518).
The spelling of 113233030301207 in words is "one hundred thirteen trillion, two hundred thirty-three billion, thirty million, three hundred one thousand, two hundred seven".
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