Base | Representation |
---|---|
bin | 1010010011000110100111… |
… | …1011100011100110000110 |
3 | 1111002111110000100211012212 |
4 | 2210301221323203212012 |
5 | 2441010120104342410 |
6 | 40025505100343422 |
7 | 2246040126351530 |
oct | 244615173434606 |
9 | 44074400324185 |
10 | 11323311012230 |
11 | 3676209960778 |
12 | 132a649b44b72 |
13 | 641a25897109 |
14 | 2b20a0604850 |
15 | 14982a60eb05 |
hex | a4c69ee3986 |
11323311012230 has 16 divisors (see below), whose sum is σ = 23293668368160. Its totient is φ = 3882278061312.
The previous prime is 11323311012227. The next prime is 11323311012287. The reversal of 11323311012230 is 3221011332311.
11323311012230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11323311012196 and 11323311012205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80880792875 + ... + 80880793014.
It is an arithmetic number, because the mean of its divisors is an integer number (1455854273010).
Almost surely, 211323311012230 is an apocalyptic number.
11323311012230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11323311012230 is an abundant number, since it is smaller than the sum of its proper divisors (11970357355930).
11323311012230 is a wasteful number, since it uses less digits than its factorization.
11323311012230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161761585903.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11323311012230 its reverse (3221011332311), we get a palindrome (14544322344541).
The spelling of 11323311012230 in words is "eleven trillion, three hundred twenty-three billion, three hundred eleven million, twelve thousand, two hundred thirty".
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