Base | Representation |
---|---|
bin | 1010010011000110101010… |
… | …1001101011010001110011 |
3 | 1111002111110212010001201002 |
4 | 2210301222221223101303 |
5 | 2441010131203233243 |
6 | 40025510211432215 |
7 | 2246040334204601 |
oct | 244615251532163 |
9 | 44074425101632 |
10 | 11323323102323 |
11 | 3676215769191 |
12 | 132a651bb566b |
13 | 641a2823b10b |
14 | 2b20a2070871 |
15 | 14982b6ebeb8 |
hex | a4c6aa6b473 |
11323323102323 has 2 divisors, whose sum is σ = 11323323102324. Its totient is φ = 11323323102322.
The previous prime is 11323323102293. The next prime is 11323323102337. The reversal of 11323323102323 is 32320132332311.
11323323102323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11323323102323 - 214 = 11323323085939 is a prime.
It is not a weakly prime, because it can be changed into another prime (11323323102023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661661551161 + 5661661551162.
It is an arithmetic number, because the mean of its divisors is an integer number (5661661551162).
Almost surely, 211323323102323 is an apocalyptic number.
11323323102323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323323102323 is an equidigital number, since it uses as much as digits as its factorization.
11323323102323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 11323323102323 its reverse (32320132332311), we get a palindrome (43643455434634).
The spelling of 11323323102323 in words is "eleven trillion, three hundred twenty-three billion, three hundred twenty-three million, one hundred two thousand, three hundred twenty-three".
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