Base | Representation |
---|---|
bin | 1010010011000110101010… |
… | …1001101011010001010101 |
3 | 1111002111110212010001122222 |
4 | 2210301222221223101111 |
5 | 2441010131203233133 |
6 | 40025510211432125 |
7 | 2246040334204526 |
oct | 244615251532125 |
9 | 44074425101588 |
10 | 11323323102293 |
11 | 3676215769164 |
12 | 132a651bb5645 |
13 | 641a2823b0b7 |
14 | 2b20a207084d |
15 | 14982b6ebe98 |
hex | a4c6aa6b455 |
11323323102293 has 2 divisors, whose sum is σ = 11323323102294. Its totient is φ = 11323323102292.
The previous prime is 11323323102269. The next prime is 11323323102323. The reversal of 11323323102293 is 39220132332311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11140154509969 + 183168592324 = 3337687^2 + 427982^2 .
It is a cyclic number.
It is not a de Polignac number, because 11323323102293 - 214 = 11323323085909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323323102593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661661551146 + 5661661551147.
It is an arithmetic number, because the mean of its divisors is an integer number (5661661551147).
Almost surely, 211323323102293 is an apocalyptic number.
It is an amenable number.
11323323102293 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323323102293 is an equidigital number, since it uses as much as digits as its factorization.
11323323102293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 35.
The spelling of 11323323102293 in words is "eleven trillion, three hundred twenty-three billion, three hundred twenty-three million, one hundred two thousand, two hundred ninety-three".
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