11323340431 has 4 divisors (see below), whose sum is σ = 12194366632. Its totient is φ = 10452314232.

The previous prime is 11323340423. The next prime is 11323340437. The reversal of 11323340431 is 13404332311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13404332311 = 23 ⋅582797057.

It is a cyclic number.

It is not a de Polignac number, because 11323340431 - 2³ = 11323340423 is a prime.

It is a super-2 number, since 2×11323340431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11323340396 and 11323340405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11323340437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435513081 + ... + 435513106.

It is an arithmetic number, because the mean of its divisors is an integer number (3048591658).

Almost surely, 2^11323340431 is an apocalyptic number.

11323340431 is a deficient number, since it is larger than the sum of its proper divisors (871026201).

11323340431 is an equidigital number, since it uses as much as digits as its factorization.

11323340431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 871026200.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11323340431 its reverse (13404332311), we get a palindrome (24727672742).

It can be divided in two parts, 113233 and 40431, that added together give a square (153664 = 392²).

The spelling of 11323340431 in words is "eleven billion, three hundred twenty-three million, three hundred forty thousand, four hundred thirty-one".