11323340437 has 2 divisors, whose sum is σ = 11323340438. Its totient is φ = 11323340436.

The previous prime is 11323340423. The next prime is 11323340477. The reversal of 11323340437 is 73404332311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8733650116 + 2589690321 = 93454^2 + 50889^2 .

It is a cyclic number.

It is not a de Polignac number, because 11323340437 - 2¹⁵ = 11323307669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11323340399 and 11323340408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11323340407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661670218 + 5661670219.

It is an arithmetic number, because the mean of its divisors is an integer number (5661670219).

Almost surely, 2^11323340437 is an apocalyptic number.

It is an amenable number.

11323340437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323340437 is an equidigital number, since it uses as much as digits as its factorization.

11323340437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 31.

Adding to 11323340437 its reverse (73404332311), we get a palindrome (84727672748).

The spelling of 11323340437 in words is "eleven billion, three hundred twenty-three million, three hundred forty thousand, four hundred thirty-seven".