Base | Representation |
---|---|
bin | 10101000101111011… |
… | …01110010011010001 |
3 | 1002020012011000121221 |
4 | 22202331232103101 |
5 | 141142422232032 |
6 | 5111401045041 |
7 | 550422421165 |
oct | 124275562321 |
9 | 32205130557 |
10 | 11324024017 |
11 | 4891130939 |
12 | 2240486781 |
13 | 10b60b7337 |
14 | 795d38ca5 |
15 | 464246597 |
hex | 2a2f6e4d1 |
11324024017 has 2 divisors, whose sum is σ = 11324024018. Its totient is φ = 11324024016.
The previous prime is 11324023993. The next prime is 11324024021. The reversal of 11324024017 is 71042042311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6323271361 + 5000752656 = 79519^2 + 70716^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11324024017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11324023982 and 11324024000.
It is not a weakly prime, because it can be changed into another prime (11324024027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662012008 + 5662012009.
It is an arithmetic number, because the mean of its divisors is an integer number (5662012009).
Almost surely, 211324024017 is an apocalyptic number.
It is an amenable number.
11324024017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11324024017 is an equidigital number, since it uses as much as digits as its factorization.
11324024017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 11324024017 its reverse (71042042311), we get a palindrome (82366066328).
The spelling of 11324024017 in words is "eleven billion, three hundred twenty-four million, twenty-four thousand, seventeen".
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