Base | Representation |
---|---|
bin | 11001101111110111111001… |
… | …110100011001101000011111 |
3 | 112211221201211021101220020022 |
4 | 121233313321310121220133 |
5 | 104320320034012203203 |
6 | 1040502110555542355 |
7 | 32565251434254323 |
oct | 3157677164315037 |
9 | 484851737356208 |
10 | 113241004022303 |
11 | 3309a270646a03 |
12 | 1084aa4715a9bb |
13 | 4b257721baa01 |
14 | 1dd6c7299d983 |
15 | d159d20daa38 |
hex | 66fdf9d19a1f |
113241004022303 has 2 divisors, whose sum is σ = 113241004022304. Its totient is φ = 113241004022302.
The previous prime is 113241004022203. The next prime is 113241004022353. The reversal of 113241004022303 is 303220400142311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113241004022303 - 230 = 113239930280479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113241004022353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620502011151 + 56620502011152.
It is an arithmetic number, because the mean of its divisors is an integer number (56620502011152).
Almost surely, 2113241004022303 is an apocalyptic number.
113241004022303 is a deficient number, since it is larger than the sum of its proper divisors (1).
113241004022303 is an equidigital number, since it uses as much as digits as its factorization.
113241004022303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 113241004022303 its reverse (303220400142311), we get a palindrome (416461404164614).
The spelling of 113241004022303 in words is "one hundred thirteen trillion, two hundred forty-one billion, four million, twenty-two thousand, three hundred three".
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