Base | Representation |
---|---|
bin | 10101000101111100… |
… | …01000011100101111 |
3 | 1002020012100110112200 |
4 | 22202332020130233 |
5 | 141142434143434 |
6 | 5111403232543 |
7 | 550423345350 |
oct | 124276103457 |
9 | 32205313480 |
10 | 11324131119 |
11 | 48911a4354 |
12 | 2240518753 |
13 | 10b6124002 |
14 | 795d65d27 |
15 | 464268199 |
hex | 2a2f8872f |
11324131119 has 96 divisors (see below), whose sum is σ = 19975887360. Its totient is φ = 6038323200.
The previous prime is 11324131109. The next prime is 11324131123. The reversal of 11324131119 is 91113142311.
11324131119 is a `hidden beast` number, since 1 + 132 + 413 + 1 + 119 = 666.
It is not a de Polignac number, because 11324131119 - 28 = 11324130863 is a prime.
It is a super-2 number, since 2×113241311192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11324131092 and 11324131101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324131109) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 40299259 + ... + 40299539.
It is an arithmetic number, because the mean of its divisors is an integer number (208082160).
Almost surely, 211324131119 is an apocalyptic number.
11324131119 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
11324131119 is a deficient number, since it is larger than the sum of its proper divisors (8651756241).
11324131119 is a wasteful number, since it uses less digits than its factorization.
11324131119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 701 (or 698 counting only the distinct ones).
The product of its digits is 648, while the sum is 27.
The spelling of 11324131119 in words is "eleven billion, three hundred twenty-four million, one hundred thirty-one thousand, one hundred nineteen".
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