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1132413112300 = 225211324131123
BaseRepresentation
bin10000011110101001000…
…101001100111111101100
311000020221211001110212111
4100132221011030333230
5122023140224043200
62224120131013404
7144546152431141
oct20365105147754
94006854043774
101132413112300
113a7287753008
12163576a3a264
1382a2b09a372
143cb481c63c8
151e6cb3910ba
hex107a914cfec

1132413112300 has 18 divisors (see below), whose sum is σ = 2457336453908. Its totient is φ = 452965244880.

The previous prime is 1132413112277. The next prime is 1132413112333. The reversal of 1132413112300 is 32113142311.

It is a super-2 number, since 2×11324131123002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5662065462 + ... + 5662065661.

Almost surely, 21132413112300 is an apocalyptic number.

1132413112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1132413112300 is an abundant number, since it is smaller than the sum of its proper divisors (1324923341608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1132413112300 is a wasteful number, since it uses less digits than its factorization.

1132413112300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11324131137 (or 11324131130 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1132413112300 its reverse (32113142311), we get a palindrome (1164526254611).

The spelling of 1132413112300 in words is "one trillion, one hundred thirty-two billion, four hundred thirteen million, one hundred twelve thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 11324131123 22648262246 45296524492 56620655615 113241311230 226482622460 283103278075 566206556150 1132413112300