Base | Representation |
---|---|
bin | 110100101110110110… |
… | …1101011001111111101 |
3 | 101211021222200101022101 |
4 | 1221131231223033331 |
5 | 3323404244420123 |
6 | 124004500145101 |
7 | 11116141025044 |
oct | 1513555531775 |
9 | 354258611271 |
10 | 113241404413 |
11 | 44030903235 |
12 | 19b44398191 |
13 | a8a8c04597 |
14 | 56a38a955b |
15 | 2e2b973aad |
hex | 1a5db6b3fd |
113241404413 has 2 divisors, whose sum is σ = 113241404414. Its totient is φ = 113241404412.
The previous prime is 113241404387. The next prime is 113241404443. The reversal of 113241404413 is 314404142311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68923576089 + 44317828324 = 262533^2 + 210518^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113241404413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113241404443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620702206 + 56620702207.
It is an arithmetic number, because the mean of its divisors is an integer number (56620702207).
Almost surely, 2113241404413 is an apocalyptic number.
It is an amenable number.
113241404413 is a deficient number, since it is larger than the sum of its proper divisors (1).
113241404413 is an equidigital number, since it uses as much as digits as its factorization.
113241404413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 113241404413 its reverse (314404142311), we get a palindrome (427645546724).
The spelling of 113241404413 in words is "one hundred thirteen billion, two hundred forty-one million, four hundred four thousand, four hundred thirteen".
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