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113242012319987 is a prime number
BaseRepresentation
bin11001101111111000110101…
…111010110000000011110011
3112211221211102112200201121222
4121233320311322300003303
5104320324120123214422
61040502355015135255
732565315426534605
oct3157706572600363
9484854375621558
10113242012319987
113309a738817981
121084b08897452b
134b258a3071965
141dd6d2a86b175
15d15a408aa842
hex66fe35eb00f3

113242012319987 has 2 divisors, whose sum is σ = 113242012319988. Its totient is φ = 113242012319986.

The previous prime is 113242012319983. The next prime is 113242012320023. The reversal of 113242012319987 is 789913210242311.

It is a weak prime.

It is an emirp because it is prime and its reverse (789913210242311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113242012319987 - 22 = 113242012319983 is a prime.

It is not a weakly prime, because it can be changed into another prime (113242012319983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56621006159993 + 56621006159994.

It is an arithmetic number, because the mean of its divisors is an integer number (56621006159994).

Almost surely, 2113242012319987 is an apocalyptic number.

113242012319987 is a deficient number, since it is larger than the sum of its proper divisors (1).

113242012319987 is an equidigital number, since it uses as much as digits as its factorization.

113242012319987 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 53.

The spelling of 113242012319987 in words is "one hundred thirteen trillion, two hundred forty-two billion, twelve million, three hundred nineteen thousand, nine hundred eighty-seven".