113242421000131 has 2 divisors, whose sum is σ = 113242421000132. Its totient is φ = 113242421000130.

The previous prime is 113242421000119. The next prime is 113242421000147. The reversal of 113242421000131 is 131000124242311.

It is a weak prime.

It is an emirp because it is prime and its reverse (131000124242311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113242421000131 - 2⁵ = 113242421000099 is a prime.

It is a super-2 number, since 2×113242421000131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113242421000096 and 113242421000105.

It is not a weakly prime, because it can be changed into another prime (113242421006131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56621210500065 + 56621210500066.

It is an arithmetic number, because the mean of its divisors is an integer number (56621210500066).

Almost surely, 2^{113242421000131} is an apocalyptic number.

113242421000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113242421000131 is an equidigital number, since it uses as much as digits as its factorization.

113242421000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 113242421000131 its reverse (131000124242311), we get a palindrome (244242545242442).

The spelling of 113242421000131 in words is "one hundred thirteen trillion, two hundred forty-two billion, four hundred twenty-one million, one hundred thirty-one", and thus it is an aban number.