Base | Representation |
---|---|
bin | 110100101110111010… |
… | …0111101001101101001 |
3 | 101211022010021100101211 |
4 | 1221131310331031221 |
5 | 3323410242004001 |
6 | 124005005113121 |
7 | 11116163164330 |
oct | 1513564751551 |
9 | 354263240354 |
10 | 113243313001 |
11 | 44031997185 |
12 | 19b44b587a1 |
13 | a8a9422220 |
14 | 56a3c44d17 |
15 | 2e2bbee351 |
hex | 1a5dd3d369 |
113243313001 has 32 divisors (see below), whose sum is σ = 148701788928. Its totient is φ = 83684689920.
The previous prime is 113243312971. The next prime is 113243313031. The reversal of 113243313001 is 100313342311.
It is an interprime number because it is at equal distance from previous prime (113243312971) and next prime (113243313031).
It is not a de Polignac number, because 113243313001 - 213 = 113243304809 is a prime.
It is a super-3 number, since 3×1132433130013 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (113243313031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 76740 + ... + 482053.
It is an arithmetic number, because the mean of its divisors is an integer number (4646930904).
Almost surely, 2113243313001 is an apocalyptic number.
It is an amenable number.
113243313001 is a deficient number, since it is larger than the sum of its proper divisors (35458475927).
113243313001 is a wasteful number, since it uses less digits than its factorization.
113243313001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 558961.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 113243313001 its reverse (100313342311), we get a palindrome (213556655312).
The spelling of 113243313001 in words is "one hundred thirteen billion, two hundred forty-three million, three hundred thirteen thousand, one".
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