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11324433121 is a prime number
BaseRepresentation
bin10101000101111110…
…10010001011100001
31002020012220210210221
422202333102023201
5141143023324441
65111413523041
7550426044001
oct124277221341
932205823727
1011324433121
114891390241
122240643481
1310b61cb601
14796004001
154642c78d1
hex2a2fd22e1

11324433121 has 2 divisors, whose sum is σ = 11324433122. Its totient is φ = 11324433120.

The previous prime is 11324433077. The next prime is 11324433139. The reversal of 11324433121 is 12133442311.

11324433121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10673162721 + 651270400 = 103311^2 + 25520^2 .

It is a cyclic number.

It is not a de Polignac number, because 11324433121 - 211 = 11324431073 is a prime.

It is not a weakly prime, because it can be changed into another prime (11324433151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662216560 + 5662216561.

It is an arithmetic number, because the mean of its divisors is an integer number (5662216561).

Almost surely, 211324433121 is an apocalyptic number.

It is an amenable number.

11324433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11324433121 is an equidigital number, since it uses as much as digits as its factorization.

11324433121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

Adding to 11324433121 its reverse (12133442311), we get a palindrome (23457875432).

The spelling of 11324433121 in words is "eleven billion, three hundred twenty-four million, four hundred thirty-three thousand, one hundred twenty-one".