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1132513367981 is a prime number
BaseRepresentation
bin10000011110101111000…
…011101001011110101101
311000021012210200222210212
4100132233003221132231
5122023341410233411
62224134111512205
7144551510536562
oct20365703513655
94007183628725
101132513367981
113a73292a9646
121635a4528665
1382a45aa0358
143cb57642869
151e6d509668b
hex107af0e97ad

1132513367981 has 2 divisors, whose sum is σ = 1132513367982. Its totient is φ = 1132513367980.

The previous prime is 1132513367939. The next prime is 1132513368013. The reversal of 1132513367981 is 1897633152311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1093574239081 + 38939128900 = 1045741^2 + 197330^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132513367981 - 218 = 1132513105837 is a prime.

It is a super-2 number, since 2×11325133679812 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1132510367981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566256683990 + 566256683991.

It is an arithmetic number, because the mean of its divisors is an integer number (566256683991).

Almost surely, 21132513367981 is an apocalyptic number.

It is an amenable number.

1132513367981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132513367981 is an equidigital number, since it uses as much as digits as its factorization.

1132513367981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 816480, while the sum is 50.

The spelling of 1132513367981 in words is "one trillion, one hundred thirty-two billion, five hundred thirteen million, three hundred sixty-seven thousand, nine hundred eighty-one".