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113252383597 is a prime number
BaseRepresentation
bin110100101111001011…
…1100011101101101101
3101211022202100011220211
41221132113203231231
53323420102233342
6124005531342421
711116333243243
oct1513627435555
9354282304824
10113252383597
1144037022041
1219b47bb1a11
13a8ab279a42
1456a5126793
152e2c8e1c17
hex1a5e5e3b6d

113252383597 has 2 divisors, whose sum is σ = 113252383598. Its totient is φ = 113252383596.

The previous prime is 113252383591. The next prime is 113252383613. The reversal of 113252383597 is 795383252311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86087080836 + 27165302761 = 293406^2 + 164819^2 .

It is a cyclic number.

It is not a de Polignac number, because 113252383597 - 27 = 113252383469 is a prime.

It is a super-2 number, since 2×1132523835972 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113252383597.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113252383591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626191798 + 56626191799.

It is an arithmetic number, because the mean of its divisors is an integer number (56626191799).

Almost surely, 2113252383597 is an apocalyptic number.

It is an amenable number.

113252383597 is a deficient number, since it is larger than the sum of its proper divisors (1).

113252383597 is an equidigital number, since it uses as much as digits as its factorization.

113252383597 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1360800, while the sum is 49.

The spelling of 113252383597 in words is "one hundred thirteen billion, two hundred fifty-two million, three hundred eighty-three thousand, five hundred ninety-seven".