Base | Representation |
---|---|
bin | 10101000110000100… |
… | …11000000000001011 |
3 | 1002020021102222022101 |
4 | 22203002120000023 |
5 | 141143230242103 |
6 | 5111443134231 |
7 | 550435660225 |
oct | 124302300013 |
9 | 32207388271 |
10 | 11325243403 |
11 | 4891893aa1 |
12 | 2240974377 |
13 | 10b6423376 |
14 | 796175415 |
15 | 4643d7a1d |
hex | 2a309800b |
11325243403 has 2 divisors, whose sum is σ = 11325243404. Its totient is φ = 11325243402.
The previous prime is 11325243367. The next prime is 11325243421. The reversal of 11325243403 is 30434252311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11325243403 - 29 = 11325242891 is a prime.
It is a super-2 number, since 2×113252434032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11325243463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662621701 + 5662621702.
It is an arithmetic number, because the mean of its divisors is an integer number (5662621702).
Almost surely, 211325243403 is an apocalyptic number.
11325243403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11325243403 is an equidigital number, since it uses as much as digits as its factorization.
11325243403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 11325243403 its reverse (30434252311), we get a palindrome (41759495714).
The spelling of 11325243403 in words is "eleven billion, three hundred twenty-five million, two hundred forty-three thousand, four hundred three".
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