Base | Representation |
---|---|
bin | 1010010011001101110110… |
… | …0101111110111100000111 |
3 | 1111002200110020202112101012 |
4 | 2210303131211332330013 |
5 | 2441023103341422434 |
6 | 40030425420152435 |
7 | 2246136201346454 |
oct | 244633545767407 |
9 | 44080406675335 |
10 | 11325251514119 |
11 | 367701525a544 |
12 | 132aaab99871b |
13 | 641c7490ba9a |
14 | 2b220621282b |
15 | 1498e0b6d3ce |
hex | a4cdd97ef07 |
11325251514119 has 2 divisors, whose sum is σ = 11325251514120. Its totient is φ = 11325251514118.
The previous prime is 11325251514077. The next prime is 11325251514169. The reversal of 11325251514119 is 91141515252311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11325251514119 - 216 = 11325251448583 is a prime.
It is a super-2 number, since 2×113252515141192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11325251514169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662625757059 + 5662625757060.
It is an arithmetic number, because the mean of its divisors is an integer number (5662625757060).
Almost surely, 211325251514119 is an apocalyptic number.
11325251514119 is a deficient number, since it is larger than the sum of its proper divisors (1).
11325251514119 is an equidigital number, since it uses as much as digits as its factorization.
11325251514119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54000, while the sum is 41.
The spelling of 11325251514119 in words is "eleven trillion, three hundred twenty-five billion, two hundred fifty-one million, five hundred fourteen thousand, one hundred nineteen".
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