Base | Representation |
---|---|
bin | 110100101111001100… |
… | …0100011101001000111 |
3 | 101211022202211111002222 |
4 | 1221132120203221013 |
5 | 3323420134123242 |
6 | 124005541122555 |
7 | 11116335413534 |
oct | 1513630435107 |
9 | 354282744088 |
10 | 113252645447 |
11 | 44037190847 |
12 | 19b480b945b |
13 | a8ab33bc96 |
14 | 56a5193d8b |
15 | 2e2c9445d2 |
hex | 1a5e623a47 |
113252645447 has 2 divisors, whose sum is σ = 113252645448. Its totient is φ = 113252645446.
The previous prime is 113252645419. The next prime is 113252645453. The reversal of 113252645447 is 744546252311.
It is a strong prime.
It is an emirp because it is prime and its reverse (744546252311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113252645447 - 26 = 113252645383 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113252645398 and 113252645407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113252645347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626322723 + 56626322724.
It is an arithmetic number, because the mean of its divisors is an integer number (56626322724).
Almost surely, 2113252645447 is an apocalyptic number.
113252645447 is a deficient number, since it is larger than the sum of its proper divisors (1).
113252645447 is an equidigital number, since it uses as much as digits as its factorization.
113252645447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 806400, while the sum is 44.
Adding to 113252645447 its reverse (744546252311), we get a palindrome (857798897758).
The spelling of 113252645447 in words is "one hundred thirteen billion, two hundred fifty-two million, six hundred forty-five thousand, four hundred forty-seven".
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