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1132530405473 is a prime number
BaseRepresentation
bin10000011110110000000…
…100101001000001100001
311000021020222202120212002
4100132300010221001201
5122023410240433343
62224135521013345
7144552105416555
oct20366004510141
94007228676762
101132530405473
113a7337986115
121635aa184255
1382a494871cc
143cb599d9865
151e6d680e8b8
hex107b0129061

1132530405473 has 2 divisors, whose sum is σ = 1132530405474. Its totient is φ = 1132530405472.

The previous prime is 1132530405463. The next prime is 1132530405647. The reversal of 1132530405473 is 3745040352311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1029561296929 + 102969108544 = 1014673^2 + 320888^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132530405473 - 210 = 1132530404449 is a prime.

It is not a weakly prime, because it can be changed into another prime (1132530405463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566265202736 + 566265202737.

It is an arithmetic number, because the mean of its divisors is an integer number (566265202737).

Almost surely, 21132530405473 is an apocalyptic number.

It is an amenable number.

1132530405473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132530405473 is an equidigital number, since it uses as much as digits as its factorization.

1132530405473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

Adding to 1132530405473 its reverse (3745040352311), we get a palindrome (4877570757784).

The spelling of 1132530405473 in words is "one trillion, one hundred thirty-two billion, five hundred thirty million, four hundred five thousand, four hundred seventy-three".