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113253226231 is a prime number
BaseRepresentation
bin110100101111001101…
…0110001011011110111
3101211022210220222210111
41221132122301123313
53323420311214411
6124010001403451
711116343353015
oct1513632613367
9354283828714
10113253226231
1144037548132
1219b48339587
13a8ab4b3442
1456a52a58b5
152e2ca0b721
hex1a5e6b16f7

113253226231 has 2 divisors, whose sum is σ = 113253226232. Its totient is φ = 113253226230.

The previous prime is 113253226193. The next prime is 113253226241. The reversal of 113253226231 is 132622352311.

It is a strong prime.

It is an emirp because it is prime and its reverse (132622352311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113253226231 - 27 = 113253226103 is a prime.

It is a super-2 number, since 2×1132532262312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113253226193 and 113253226202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113253226241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626613115 + 56626613116.

It is an arithmetic number, because the mean of its divisors is an integer number (56626613116).

Almost surely, 2113253226231 is an apocalyptic number.

113253226231 is a deficient number, since it is larger than the sum of its proper divisors (1).

113253226231 is an equidigital number, since it uses as much as digits as its factorization.

113253226231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 31.

Adding to 113253226231 its reverse (132622352311), we get a palindrome (245875578542).

The spelling of 113253226231 in words is "one hundred thirteen billion, two hundred fifty-three million, two hundred twenty-six thousand, two hundred thirty-one".