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11325437 is a prime number
BaseRepresentation
bin101011001100…
…111111111101
3210022101120122
4223030333331
510344403222
61042424325
7165156524
oct53147775
923271518
1011325437
116435a72
1239620a5
132466c56
14170b4bb
15edaa42
hexaccffd

11325437 has 2 divisors, whose sum is σ = 11325438. Its totient is φ = 11325436.

The previous prime is 11325421. The next prime is 11325473. The reversal of 11325437 is 73452311.

Together with next prime (11325473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10023556 + 1301881 = 3166^2 + 1141^2 .

It is an emirp because it is prime and its reverse (73452311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11325437 - 24 = 11325421 is a prime.

It is a nialpdrome in base 15.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11325487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662718 + 5662719.

It is an arithmetic number, because the mean of its divisors is an integer number (5662719).

Almost surely, 211325437 is an apocalyptic number.

It is an amenable number.

11325437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325437 is an equidigital number, since it uses as much as digits as its factorization.

11325437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2520, while the sum is 26.

The square root of 11325437 is about 3365.3286615129. The cubic root of 11325437 is about 224.5699571830.

Adding to 11325437 its reverse (73452311), we get a palindrome (84777748).

The spelling of 11325437 in words is "eleven million, three hundred twenty-five thousand, four hundred thirty-seven".