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113254515224069 is a prime number
BaseRepresentation
bin11001110000000100011111…
…001001100010111000000101
3112212000000200220010001200112
4121300010133021202320011
5104321030221344132234
61040512223411522405
732566240315502162
oct3160043711427005
9485000626101615
10113254515224069
11330a4a7433985a
1210851597bb9405
134b26b1646735b
141dd7795199069
15d16023369ace
hex67011f262e05

113254515224069 has 2 divisors, whose sum is σ = 113254515224070. Its totient is φ = 113254515224068.

The previous prime is 113254515223979. The next prime is 113254515224093. The reversal of 113254515224069 is 960422515452311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84292358501569 + 28962156722500 = 9181087^2 + 5381650^2 .

It is a cyclic number.

It is not a de Polignac number, because 113254515224069 - 224 = 113254498446853 is a prime.

It is a super-2 number, since 2×1132545152240692 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113254515224369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56627257612034 + 56627257612035.

It is an arithmetic number, because the mean of its divisors is an integer number (56627257612035).

Almost surely, 2113254515224069 is an apocalyptic number.

It is an amenable number.

113254515224069 is a deficient number, since it is larger than the sum of its proper divisors (1).

113254515224069 is an equidigital number, since it uses as much as digits as its factorization.

113254515224069 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592000, while the sum is 50.

The spelling of 113254515224069 in words is "one hundred thirteen trillion, two hundred fifty-four billion, five hundred fifteen million, two hundred twenty-four thousand, sixty-nine".