11325514001004 has 108 divisors (see below), whose sum is σ = 33396747189624. Its totient is φ = 3226694220288.

The previous prime is 11325514000987. The next prime is 11325514001057. The reversal of 11325514001004 is 40010041552311.

11325514001004 is a `hidden beast` number, since 1 + 1 + 3 + 2 + 551 + 4 + 0 + 0 + 100 + 4 = 666.

It is a super-2 number, since 2×11325514001004² (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 8471302 + ... + 9716685.

Almost surely, 2^{11325514001004} is an apocalyptic number.

11325514001004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

11325514001004 is an abundant number, since it is smaller than the sum of its proper divisors (22071233188620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11325514001004 is a wasteful number, since it uses less digits than its factorization.

11325514001004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18188364 (or 18188352 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 11325514001004 its reverse (40010041552311), we get a palindrome (51335555553315).

The spelling of 11325514001004 in words is "eleven trillion, three hundred twenty-five billion, five hundred fourteen million, one thousand, four".