11325514001057 has 2 divisors, whose sum is σ = 11325514001058. Its totient is φ = 11325514001056.

The previous prime is 11325514000987. The next prime is 11325514001059. The reversal of 11325514001057 is 75010041552311.

11325514001057 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11290130886241 + 35383114816 = 3360079^2 + 188104^2 .

It is a cyclic number.

It is not a de Polignac number, because 11325514001057 - 2⁴⁰ = 10226002373281 is a prime.

Together with 11325514001059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11325514001059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662757000528 + 5662757000529.

It is an arithmetic number, because the mean of its divisors is an integer number (5662757000529).

Almost surely, 2^{11325514001057} is an apocalyptic number.

It is an amenable number.

11325514001057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325514001057 is an equidigital number, since it uses as much as digits as its factorization.

11325514001057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21000, while the sum is 35.

Adding to 11325514001057 its reverse (75010041552311), we get a palindrome (86335555553368).

The spelling of 11325514001057 in words is "eleven trillion, three hundred twenty-five billion, five hundred fourteen million, one thousand, fifty-seven".