11325514001531 has 2 divisors, whose sum is σ = 11325514001532. Its totient is φ = 11325514001530.

The previous prime is 11325514001489. The next prime is 11325514001561. The reversal of 11325514001531 is 13510041552311.

It is a strong prime.

It is an emirp because it is prime and its reverse (13510041552311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11325514001531 - 2²⁶ = 11325446892667 is a prime.

It is a super-2 number, since 2×11325514001531² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11325514001561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662757000765 + 5662757000766.

It is an arithmetic number, because the mean of its divisors is an integer number (5662757000766).

Almost surely, 2^{11325514001531} is an apocalyptic number.

11325514001531 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325514001531 is an equidigital number, since it uses as much as digits as its factorization.

11325514001531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 11325514001531 its reverse (13510041552311), we get a palindrome (24835555553842).

The spelling of 11325514001531 in words is "eleven trillion, three hundred twenty-five billion, five hundred fourteen million, one thousand, five hundred thirty-one".