11325520000051 has 2 divisors, whose sum is σ = 11325520000052. Its totient is φ = 11325520000050.

The previous prime is 11325520000031. The next prime is 11325520000111. The reversal of 11325520000051 is 15000002552311.

11325520000051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11325520000051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11325519999980 and 11325520000025.

It is not a weakly prime, because it can be changed into another prime (11325520000031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662760000025 + 5662760000026.

It is an arithmetic number, because the mean of its divisors is an integer number (5662760000026).

Almost surely, 2^{11325520000051} is an apocalyptic number.

11325520000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325520000051 is an equidigital number, since it uses as much as digits as its factorization.

11325520000051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 11325520000051 its reverse (15000002552311), we get a palindrome (26325522552362).

The spelling of 11325520000051 in words is "eleven trillion, three hundred twenty-five billion, five hundred twenty million, fifty-one", and thus it is an aban number.