Base | Representation |
---|---|
bin | 1010010011001110110110… |
… | …0110001011010110011011 |
3 | 1111002201010221222001022221 |
4 | 2210303231212023112123 |
5 | 2441024131110003121 |
6 | 40030512210524511 |
7 | 2246145641424361 |
oct | 244635546132633 |
9 | 44081127861287 |
10 | 11325520000411 |
11 | 367714286a241 |
12 | 132ab65896737 |
13 | 641cb8424906 |
14 | 2b222db41631 |
15 | 149909504b41 |
hex | a4ced98b59b |
11325520000411 has 2 divisors, whose sum is σ = 11325520000412. Its totient is φ = 11325520000410.
The previous prime is 11325520000397. The next prime is 11325520000463. The reversal of 11325520000411 is 11400002552311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11325520000411 - 213 = 11325519992219 is a prime.
It is not a weakly prime, because it can be changed into another prime (11325520000471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662760000205 + 5662760000206.
It is an arithmetic number, because the mean of its divisors is an integer number (5662760000206).
Almost surely, 211325520000411 is an apocalyptic number.
11325520000411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11325520000411 is an equidigital number, since it uses as much as digits as its factorization.
11325520000411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 11325520000411 its reverse (11400002552311), we get a palindrome (22725522552722).
The spelling of 11325520000411 in words is "eleven trillion, three hundred twenty-five billion, five hundred twenty million, four hundred eleven", and thus it is an aban number.
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