Base | Representation |
---|---|
bin | 110100110000000100… |
… | …0100101100001001011 |
3 | 101211101211002112011201 |
4 | 1221200020211201023 |
5 | 3324000143411014 |
6 | 124012510405031 |
7 | 11120143140142 |
oct | 1514010454113 |
9 | 354354075151 |
10 | 113282013259 |
11 | 4405181a268 |
12 | 19b55b00777 |
13 | a8b445229c |
14 | 56a903a759 |
15 | 2e302e5e74 |
hex | 1a6022584b |
113282013259 has 2 divisors, whose sum is σ = 113282013260. Its totient is φ = 113282013258.
The previous prime is 113282013227. The next prime is 113282013277. The reversal of 113282013259 is 952310282311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (952310282311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113282013259 - 25 = 113282013227 is a prime.
It is a super-3 number, since 3×1132820132593 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (113282013209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56641006629 + 56641006630.
It is an arithmetic number, because the mean of its divisors is an integer number (56641006630).
Almost surely, 2113282013259 is an apocalyptic number.
113282013259 is a deficient number, since it is larger than the sum of its proper divisors (1).
113282013259 is an equidigital number, since it uses as much as digits as its factorization.
113282013259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 113282013259 in words is "one hundred thirteen billion, two hundred eighty-two million, thirteen thousand, two hundred fifty-nine".
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