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113300643542 = 294351600421
BaseRepresentation
bin110100110000100111…
…1101001111011010110
3101211110010011001010012
41221201033221323112
53324014431043132
6124014414000222
711120460402632
oct1514117517326
9354403131105
10113300643542
1144061294499
1219b601a6072
13a8b8276118
1456ab6c9dc2
152e31c760b2
hex1a613e9ed6

113300643542 has 8 divisors (see below), whose sum is σ = 169953049632. Its totient is φ = 56649627000.

The previous prime is 113300643517. The next prime is 113300643553. The reversal of 113300643542 is 245346003311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1133006435423 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113300643499 and 113300643508.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111509 + ... + 488912.

It is an arithmetic number, because the mean of its divisors is an integer number (21244131204).

Almost surely, 2113300643542 is an apocalyptic number.

113300643542 is a deficient number, since it is larger than the sum of its proper divisors (56652406090).

113300643542 is an equidigital number, since it uses as much as digits as its factorization.

113300643542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 694774.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 113300643542 its reverse (245346003311), we get a palindrome (358646646853).

The spelling of 113300643542 in words is "one hundred thirteen billion, three hundred million, six hundred forty-three thousand, five hundred forty-two".

Divisors: 1 2 94351 188702 600421 1200842 56650321771 113300643542