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113300999983 is a prime number
BaseRepresentation
bin110100110000101000…
…1000000111100101111
3101211110010211011001201
41221201101000330233
53324020023444413
6124014425350331
711120463416053
oct1514121007457
9354403734051
10113300999983
1144061508276
1219b603383a7
13a8b836c432
1456ab77dc63
152e31ce69dd
hex1a61440f2f

113300999983 has 2 divisors, whose sum is σ = 113300999984. Its totient is φ = 113300999982.

The previous prime is 113300999971. The next prime is 113301000017. The reversal of 113300999983 is 389999003311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113300999983 - 217 = 113300868911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113300999923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56650499991 + 56650499992.

It is an arithmetic number, because the mean of its divisors is an integer number (56650499992).

Almost surely, 2113300999983 is an apocalyptic number.

113300999983 is a deficient number, since it is larger than the sum of its proper divisors (1).

113300999983 is an equidigital number, since it uses as much as digits as its factorization.

113300999983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1417176, while the sum is 55.

The spelling of 113300999983 in words is "one hundred thirteen billion, three hundred million, nine hundred ninety-nine thousand, nine hundred eighty-three".