Base | Representation |
---|---|
bin | 10000011111001100110… |
… | …001110100110000010101 |
3 | 11000022111112222201212211 |
4 | 100133030301310300111 |
5 | 122030402033341203 |
6 | 2224255403313421 |
7 | 144600044125435 |
oct | 20371461646025 |
9 | 4008445881784 |
10 | 1133012012053 |
11 | 3a756481a289 |
12 | 16370351b871 |
13 | 82ac519c20c |
14 | 3cba39642c5 |
15 | 1e713c42c6d |
hex | 107ccc74c15 |
1133012012053 has 2 divisors, whose sum is σ = 1133012012054. Its totient is φ = 1133012012052.
The previous prime is 1133012012023. The next prime is 1133012012129. The reversal of 1133012012053 is 3502102103311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1008132467364 + 124879544689 = 1004058^2 + 353383^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133012012053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133012012003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566506006026 + 566506006027.
It is an arithmetic number, because the mean of its divisors is an integer number (566506006027).
Almost surely, 21133012012053 is an apocalyptic number.
It is an amenable number.
1133012012053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133012012053 is an equidigital number, since it uses as much as digits as its factorization.
1133012012053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 1133012012053 its reverse (3502102103311), we get a palindrome (4635114115364).
The spelling of 1133012012053 in words is "one trillion, one hundred thirty-three billion, twelve million, twelve thousand, fifty-three".
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