11330141411 has 2 divisors, whose sum is σ = 11330141412. Its totient is φ = 11330141410.

The previous prime is 11330141401. The next prime is 11330141413. The reversal of 11330141411 is 11414103311.

11330141411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11330141411 is a prime.

Together with 11330141413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11330141413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665070705 + 5665070706.

It is an arithmetic number, because the mean of its divisors is an integer number (5665070706).

Almost surely, 2^11330141411 is an apocalyptic number.

11330141411 is a deficient number, since it is larger than the sum of its proper divisors (1).

11330141411 is an equidigital number, since it uses as much as digits as its factorization.

11330141411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11330141411 its reverse (11414103311), we get a palindrome (22744244722).

The spelling of 11330141411 in words is "eleven billion, three hundred thirty million, one hundred forty-one thousand, four hundred eleven".