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11330310231997 is a prime number
BaseRepresentation
bin1010010011100000101100…
…0111011101011110111101
31111010011111210122000201121
42210320023013131132331
52441113433404410442
640033023410110541
72246405435631211
oct244701307353675
944104453560647
1011330310231997
113679180822119
12132ba81b7b451
1364259c988b83
142b2565dda941
15149ad9d22967
hexa4e0b1dd7bd

11330310231997 has 2 divisors, whose sum is σ = 11330310231998. Its totient is φ = 11330310231996.

The previous prime is 11330310231991. The next prime is 11330310232051. The reversal of 11330310231997 is 79913201303311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9179318408121 + 2150991823876 = 3029739^2 + 1466626^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11330310231997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11330310231991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665155115998 + 5665155115999.

It is an arithmetic number, because the mean of its divisors is an integer number (5665155115999).

Almost surely, 211330310231997 is an apocalyptic number.

It is an amenable number.

11330310231997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11330310231997 is an equidigital number, since it uses as much as digits as its factorization.

11330310231997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91854, while the sum is 43.

The spelling of 11330310231997 in words is "eleven trillion, three hundred thirty billion, three hundred ten million, two hundred thirty-one thousand, nine hundred ninety-seven".