Base | Representation |
---|---|
bin | 10000011111001110011… |
… | …101110110110100001001 |
3 | 11000022120112021112121021 |
4 | 100133032131312310021 |
5 | 122030431311111131 |
6 | 2224302254312441 |
7 | 144600536626132 |
oct | 20371635666411 |
9 | 4008515245537 |
10 | 1133040332041 |
11 | 3a7579802532 |
12 | 163710ab8721 |
13 | 82acb0065c7 |
14 | 3cba7616c89 |
15 | 1e716488e11 |
hex | 107ce776d09 |
1133040332041 has 2 divisors, whose sum is σ = 1133040332042. Its totient is φ = 1133040332040.
The previous prime is 1133040332027. The next prime is 1133040332057. The reversal of 1133040332041 is 1402330403311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1123591520016 + 9448812025 = 1059996^2 + 97205^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133040332041 - 29 = 1133040331529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1133040331997 and 1133040332015.
It is not a weakly prime, because it can be changed into another prime (1133040332341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566520166020 + 566520166021.
It is an arithmetic number, because the mean of its divisors is an integer number (566520166021).
Almost surely, 21133040332041 is an apocalyptic number.
It is an amenable number.
1133040332041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133040332041 is an equidigital number, since it uses as much as digits as its factorization.
1133040332041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1133040332041 its reverse (1402330403311), we get a palindrome (2535370735352).
The spelling of 1133040332041 in words is "one trillion, one hundred thirty-three billion, forty million, three hundred thirty-two thousand, forty-one".
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